topic Re: Link to Request Support Ticket for PUK Code Leads Back to AI Support in Get Support

Link to Request Support Ticket for PUK Code Leads Back to AI Support

Headband — Thu, 28 Aug 2025 01:58:32 GMT

My SIM is locked. I see there is a process to request a PUK code through a service ticket. However, when I click the link to go and create a service ticket, it leads me back to the generic support screens. Right now it's a circular path and I cannot get out of it.

Re: Link to Request Support Ticket for PUK Code Leads Back to AI Support

Chalupa_Batman — Thu, 28 Aug 2025 01:49:46 GMT

@Headband wrote:
My SIM is locked. I see there is a process to request a PUK code through a service ticket. However, when I click the link to go and create a service ticket, it leads me back to the generic support screens. Right now it's a circular path and I cannot get out of it.

You need to contact a CS Agent to get a PUK code.

The Public Mobile chatbot is currently unable to create trackable tickets for members who are unable to log in. So for this reason, please use the following link to contact customer service.

https://productioncommunity.publicmobile.ca/t5/notes/composepage/note-to-user-id/22437

A Customer Service Agent will reply to your community inbox here:

https://productioncommunity.publicmobile.ca/t5/notes/privatenotespage

During business hours (9 AM-10 PM EST) you can expect a response within 30 minutes, but it may be longer depending on current volumes.

Re: Link to Request Support Ticket for PUK Code Leads Back to AI Support

computergeek541 — Thu, 28 Aug 2025 01:59:14 GMT

@Headband wrote:
My SIM is locked. I see there is a process to request a PUK code through a service ticket. However, when I click the link to go and create a service ticket, it leads me back to the generic support screens. Right now it's a circular path and I cannot get out of it.

Please try this link (if you haven't already): https://widget.telus.tiia.ai/chatbot.html?botId=ZJkWuVb7Hp6EEcTIZKMZbvLwuDV&duid=2OhrPakuMpNZt4irir534YAWBuW&lang=en&